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12x^2-55x+28=0
a = 12; b = -55; c = +28;
Δ = b2-4ac
Δ = -552-4·12·28
Δ = 1681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1681}=41$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-55)-41}{2*12}=\frac{14}{24} =7/12 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-55)+41}{2*12}=\frac{96}{24} =4 $
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